# Artificial Intelligence NTA UGC NET Question Analysis

Artificial Intelligence NTA UGC NET Question Analysis

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Explanation:
Formula,
Conditional Probability Calculation,
The probability of a toothache, given evidence of a cavity,  P(toothache Ո cavity ) = 0.108 + 0.012 = 0.12 P(cavity ) = 0.108 + 0.012 + 0.072 + 0.008 = 0.2  So,Option(IV) is correct.

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Explanation:
Formula,
P(A U B) = P(A) + P(B) – P(A Ո B)
Calculation,
P(cavity U toothache) = P(cavity) + P(toothache) – P(cavity Ո toothache) P(cavity ) = 0.108 + 0.012 + 0.072 + 0.008 = 0.2 P(toothache) = 0.108 + 0.012 + 0.016 + 0.064 = 0.2 P(cavity Ո toothache) = 0.108 + 0.012 = 0.12

P(cavity U toothache) = P(cavity) + P(toothache) – P(cavity Ո toothache)
P(cavity U toothache) = 0.2 + 0.2 – 0.12 = 0.28
So, Option(III) is correct.

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Explanation:
Formula, Calculation,  P(cavity Ո (toothache U catch)) = 0.108 + 0.012 + 0.072 = 0.192 P(toothache U cavity) = 0.108 + 0.012 + 0.072 + 0.016 + 0.064 + 0.144 = 0.416  = 0.4615
So, Option(I) is correct.

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Explanation:
Calculation, P(cavity ) = 0.108 + 0.012 + 0.072 + 0.008 = 0.2

So, Option(III) is correct.

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Explanation:
Formula,
Conditional Probability Calculation,
The probability of a cavity, given evidence of a toothache,  P(cavity Ո toothache ) = 0.108 + 0.012 = 0.12 P(toothache) = 0.108 + 0.012 + 0.016 + 0.064 = 0.2  = 0.6
So,Option(IV) is correct.

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Explanation:
(A) (R ∧ E) ⇔ C
It is not equivalent to above statement. It says that all conservative(C) are Radical(R) and Electable (E).
(B) R ⇒ (E ⇔C)
It is equivalent to above statement. It says that if all person are Radical(R) then they are Electable (E) if
And only if they are Conservative (C).
(C) R ⇒ ((C⇒E) v ¬E)
R ⇒ (¬C v E v ¬E )
It is tautology, That is it is true in all condition because E is in both form (Normal Form & Complemented
Form)
(D) (¬R v ¬E v C) ∧ (¬R v ¬ C v E)
(¬R v E ⇒C) ∧ (¬R v C ⇒E)
¬R v ((E ⇒C) ∧ (C ⇒E))
¬R v (E ⇔C)
R ⇒ (E ⇔C)
It is equivalent to above statement. It says that if all person are Radical(R) then they are Electable (E) if
And only if they are Conservative (C).

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Explanation:
Statement I:
Stochastic Hill-climbing as a core Method for Evaluating Genetic Algorithms
Stochastic Hill-climbing maintains a vast population of states. next new states are created by mutation and crossover, which put together pairs of states from the population.

Hence Statement I is correct.
Statement II:
contingent solutions to nondeterministic problems
By constructing search trees AI agents use AND-OR search tree in non-deterministic environments to initiate contingent plans that achieve the destination (Target/Goal) regardless of which outcomes occur during execution.

Hence Statement II is also correct.
AND-OR search trees:
By constructing search trees we find contingent solutions to nondeterministic problems
OR nodes: in deterministic environment,
we call nodes OR nodes when the only branching is initiate by the agent’s own choices OR NODE in each state.
AND nodes: In a non-deterministic environment,
we call nodes OR nodes when branching is initiate by the environment’s choice of outcome for each action.
So the Correct Answer is Option (I).

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Explanation:
It is given that,
f(x)=x is my friend
p(x) = x is perfect
statement: some of my friends are not perfect.
There exist is used for ‘some’. Outer most part contains ∃x.
In statement , condition is ‘not perfect’ . so, we get ^ p(x).
Finally we get, ∃x(f(x)∧⌐p(x))

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Explanation: The root value is 17. so correct answer is II

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Explanation:
Defuzzification is the conversion of a fuzzy quantity to a precise quantity.
Defuzzification Methods are.
1.Mean of Maxima Method (MOM)
2.Weighted Average Method
3.Centroid of Area(COA)
4.Center of Area
5.Bisector of Area Method (BOA)
6.Center of gravity (COG)
7.Maxima Methods
8.First of Maxima Method (FOM)
9.Last of Maxima Method (LOM)
10.Center of Sums Method (COS)

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Explanation: The root value is 7. so correct answer is II

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Explanation: The root value is 5. so correct answer is III.

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