Cylinder Secondary memory – Operating System

Cylinder Secondary memory – Operating System


Question 91 UGC NET June-2020      
Comprehension: Question 91-95
concerns a disk with a sector size of 512 bytes, 2000 tracks per surface. 50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.
Ques -91: If one track of data can be transferred per revolution, then what is the data transfer rate?
A – 2,850 KBytes/second
B – 4,500 KBytes/second
C – 5,700 KBytes/second
D – 2,250 KBytes/second

Show Answer With Best Explanation

Answer : D


Question 92 UGC NET June-2020      
Question 91-95 concerns
a disk with a sector size of 512 bytes, 2000 tracks per surface. 50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.
Ques-92: Given below are two statements:
Statement I: The disk has a total number of 2000 cylinders.
Statement II: 51200 bytes is not a valid block size for the disk.
In the light of the above statements, choose the correct answer from the options given below:
A – Both Statement I and Statement II are true
B – Both Statement I and Statement II are false
C – Statement I is correct but Statement II is false
D – Statement I is incorrect but Statement II is true

Show Answer With Best Explanation

Answer : A


Question 93 UGC NET June-2020      
Comprehension:
Question 91-95 concerns

a disk with a sector size of 512 bytes, 2000 tracks per surface. 50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.
Ques-93: If T is the capacity of a track in bytes, and S is the capacity of each surface in bytes, then (T,S) = __.
A – (50 K, 50000 K)
B – (50 K, 50000 K)
C – (25 K, 50000 K)
D – (40 K, 36000 K)

Show Answer With Best Explanation

Answer : C


Question 94 UGC NET June-2020      
Comprehension:
Question 91-95 concerns

a disk with a sector size of 512 bytes, 2000 tracks per surface. 50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.
Ques-94: What is the capacity of the disk, in bytes?
A – 25,000 K
B – 500,000 K
C – 250,000 K
D – 50,000 K

Show Answer With Best Explanation

Answer : B


Question 95 UGC NET June-2020      
Comprehension:
Question 91-95 concerns

a disk with a sector size of 512 bytes, 2000 tracks per surface. 50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.
Ques-95: If the disk platters rotate at 5400 rpm (revolutions per minute), then approximately what is the maximum rotational delay?
A – 0.011 seconds
B – 0.11 seconds
C – 0.0011 seconds
D – 1.1seconds

Show Answer With Best Explanation

Answer : A


error: Content is protected !!
Open chat
1
Hi,how Can We Help You ?