Boolean Algebra UGC NET

Boolean Algebra UGC NET

Question 1➡ | NTA UGC NET November 2020
Simplified expression/s for following Boolean function
F(A,B,C,D)=Σ(0,1,2,3,6,12,13,14,15) is/are
A) A’B’+AB+A’C’D’
B) A’B’+AB+A’CD’
C) A’B’+AB+BC’D’
D) A’B’+AB+BCD’

Choose the correct answer from the options given below:
i ➥ (A) only
ii ➥ (B) only
iii ➥ (A) and (B) only
iv ➥ (B) and (D) only

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Answer: IV

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Simplified expression/s for following Boolean function F(A,B,C,D)=Σ(0,1,2,3,6,12,13,14,15) is/are A) A'B'+AB+A'C'D' B) A'B'+AB+A'CD' C) A'B'+AB+BC'D' D) A'B'+AB+BCD' Choose the correct answer from the options given below: A) (A) only B) (B) only C) (A) and (B) only D) (B) and (D) only
Simplified expression/s for following Boolean function F(A,B,C,D)=Σ(0,1,2,3,6,12,13,14,15) is/are A) A'B'+AB+A'C'D' B) A'B'+AB+A'CD' C) A'B'+AB+BC'D' D) A'B'+AB+BCD' Choose the correct answer from the options given below: A) (A) only B) (B) only C) (A) and (B) only D) (B) and (D) only

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Question 2➡ | NTA UGC NET November 2020
What kind of clauses are available in conjunctive normal form?
i ➥ Disjunction of literals
ii ➥ Disjunction of variables
iii ➥ Conjunction of literals
iv ➥ Conjunction of variables

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Answer: I

Explanation:
In Boolean logic, a formula is in conjunctive normal form (CNF) or clausal normal form if it is a conjunction of one or more clauses, where a clause is a disjunction of literals; otherwise put, it is a product of sums or an AND of ORs.

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Question 5➡ | NTA UGC NET December 2019
The Boolean AB+AB’+A’C+AC is unaffected by the value of the Boolean variable ___________.
i ➥ A
ii ➥ B
iii ➥ C
iv ➥ A, B & C

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Answer: II

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Question 7➡ | NTA UGC NET June 2019
Which of the following is principal conjunctive normal form for [(pVq) ∧ ~p → ~q] ?
i ➥ pV~q
ii ➥ pVq
iii ➥ ~p Vq
iv ➥ ~p V ~q

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Answer: I

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Question 8➡ | NTA UGC NET June 2019
Match List-I with List-II
Match List-I with List-II List-I                          List-II (a) p → q                (i) ¬(q → ¬p) (b) p v q                  (ii) p ∧ ¬q (c) p ∧ q                  (iii) ¬p → q (d) ¬(p → q)            (iv) ¬p v q Choose the correct option from those given below: A)	(a)-(ii);(b)-(iii);(c)-(i);(d)-(iv) B)	(a)-(ii);(b)-(i);(c)-(iii);(d)-(iv) C)	(a)-(iv);(b)-(i);(c)-(iii);(d)-(ii) D)	(a)-(iv);(b)-(iii);(c)-(i);(d)-(ii)
Choose the correct option from those given below:
i ➥ (a)-(ii);(b)-(iii);(c)-(i);(d)-(iv)
ii ➥ (a)-(ii);(b)-(i);(c)-(iii);(d)-(iv)
iii ➥ (a)-(iv);(b)-(i);(c)-(iii);(d)-(ii)
iv ➥ (a)-(iv);(b)-(iii);(c)-(i);(d)-(ii)

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Answer: IV

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Question 9➡ | NTA UGC NET June 2019
How many different Boolean functions of degree n are there?
i ➥ How many different Boolean functions of degree n are there? A)	22n    B)	(22)2 C)	22n-1 D)	2n
ii ➥ (22)2
iii ➥ 22n-1
iv ➥ How many different Boolean functions of degree n are there? A)	22n    B)	(22)2 C)	22n-1 D)	2n

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Answer: I

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Question 17➡ | NTA UGC NET December 2018
The boolean expression A’⋅B+A.B’+A.B is equivalent to
i ➥ A+B
ii ➥ A.B
iii ➥ (A+B)’
iv ➥ A’.B

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Answer: I

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Question 18➡ | NTA UGC NET December 2018
The relation ≤ and < on a boolean algebra are defined as :
x ≤ y and only if x ∨ y = y
x < y means x ≤ y but x ≠ y
x ≥ y means y ≤ x and
x > y means y <x

Consider the above definitions, which of the following is not true in the boolean algebra ?
(i)If x ≤ y and y ≤ z, then x ≤ z
(ii)If x ≤ y and y ≤ x, then x=y
(iii)If x < y and y < z, then x ≤ y
(iv)If x < y and y < z, then x < y
i ➥ (iv) only
ii ➥ (iii) only
iii ➥ (i) and (ii) only
iv ➥ (ii) and (iii) only

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Answer: II

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Question 19➡ | NTA UGC NET December 2018
Consider the following boolean equations :
(i) wx + w(x + y) + x(x + y)=x+wy
(ii) (wx’(y+xz’)+w’x’)y=x’y

What can you say about the above equations ?
i ➥ Both (i) and (ii) are true
ii ➥ (i) is true and (ii) is false
iii ➥ Both (i) and (ii) are false
iv ➥ (i) is false and (ii) is true

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Answer: I

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Question 20➡ | NTA UGC NET December 2018
Find the boolean expression for the logic circuit shown below :
(1-NAND gate, 2-NOR gate, 3-NOR gate)
Find the boolean expression for the logic circuit shown below : (1-NAND gate, 2-NOR gate, 3-NOR gate)  A)	AB B)	AB’ C)	A’B’ D)	A’B
i ➥ AB
ii ➥ AB’
iii ➥ A’B’
iv ➥ A’B

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Answer: I

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Question 22➡ | NTA UGC NET December 2018
Which of the following statements are true ?

(i) Every logic network is equivalent to one using just NAND gates or just NOR gates.
(ii) Boolean expressions and logic networks correspond to labelled acyclic digraphs.
(iii) No two Boolean algebras with n atoms are isomorphic.
(iv) Non-zero elements of finite Boolean algebras are not uniquely expressible as joins of atoms.
i ➥ (i) and (iv) only
ii ➥ (i) and (ii) only
iii ➥ (i), (ii) and (iii) only
iv ➥ (ii), (iii) and (iv) only

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Answer: II

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Question 29➡ | NTA UGC NET June 2018
Simplify the following using K-map : F (A, B, C, D) = Σ (0, 1, 2, 8, 9, 12, 13) + d(A, B, C, D) = Σ (10, 11, 14, 15) d stands for don’t care condition.
i ➥ A+B’D’ + BC
ii ➥ A+B’D’ + B’C’
iii ➥ A’+B’C’
iv ➥ A’+B’C’+B’D’

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Answer: II

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Question 30➡ | NTA UGC NET November 2017 Paper III
Let P, Q, R and S be Propositions. Assume that the equivalences P ⇔ (Q ∨ ¬ Q) and Q ⇔ R hold.Then the truth value of the formula
(P ∧ Q) ⇒ ((P ∧ R) ∨ S) is always:
i ➥ True
ii ➥ False
iii ➥ Same as truth table of Q
iv ➥ Same as truth table of S

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Answer: I

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Question 34➡ | NTA UGC NET November 2017 Paper II
Let A = Let A =   and B =   Find the boolean product A⊙B of the two matrices. NET Nov 2017 and B =Let A =   and B =   Find the boolean product A⊙B of the two matrices. NET Nov 2017
Find the boolean product A⊙B of the two matrices.
i ➥ Let A =   and B =   Find the boolean product A⊙B of the two matrices. NET Nov 2017
ii ➥ Let A =   and B =   Find the boolean product A⊙B of the two matrices. NET Nov 2017
iii ➥ Let A =   and B =   Find the boolean product A⊙B of the two matrices. NET Nov 2017
iv ➥ Let A =   and B =   Find the boolean product A⊙B of the two matrices. NET Nov 2017

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Answer: I

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Question 35➡ | NTA UGC NET November 2017 Paper II
The Boolean function with the Karnaugh map
Q6 (NET Nov 2017 paper II) The Boolean function with the Karnaugh map   is: A ➥ (A+C).D+B B ➥ (A+B).C+D C ➥ (A+D).C+B D ➥ (A+C).B+D
i ➥ (A+C).D+B
ii ➥ (A+B).C+D
iii ➥ (A+D).C+B
iv ➥ (A+C).B+D

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Answer: I

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Question 37➡ | NTA UGC NET November 2017 Paper II
Let P and Q be two propositions, ¬ (P ↔ Q) is equivalent to:
i ➥ P ↔ ¬ Q
ii ➥ ¬ P ↔ Q
iii ➥ ¬ P ↔ ¬ Q
iv ➥ Q → P

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Answer: I , II Both(Marks to all)

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Question 38➡ | NTA UGC NET November 2017 Paper II
The output of the following combinational circuit is F:
Q10  (NET Nov 2017 paper II)   The output of the following combinational circuit is F.  The value of F is : A ➥ P1+P’2P3 B ➥ P1+P’2P’3 C ➥ P1 +P2 P’3 D ➥ P’1 +P2 P3
The value of F is :
i ➥ P1+P’2P3
ii ➥ P1+P’2P’3
iii ➥ P1 +P2 P’3
iv ➥ P’1 +P2 P3

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Answer: II

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Question 38➡ | NTA UGC NET November 2017 Paper II
The output of the following combinational circuit is F:
Q10  (NET Nov 2017 paper II)   The output of the following combinational circuit is F.  The value of F is : A ➥ P1+P’2P3 B ➥ P1+P’2P’3 C ➥ P1 +P2 P’3 D ➥ P’1 +P2 P3
The value of F is :
i ➥ P1+P’2P3
ii ➥ P1+P’2P’3
iii ➥ P1 +P2 P’3
iv ➥ P’1 +P2 P3

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Answer: II

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