| Question 1 UGC NET June-2020 A non-pipeline system takes 50ns to process a task. The same task can be processed in a six-segment pipeline with a clock cycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks |
| A – 6 |
| B – 4.95 |
| C – 5.7 |
| D – 5.5 |
Show Answer With Best Explanation
Answer: B
Explanation:
Time required to execute 500 tasks without pipeline = 500* 50 = 25000 ns
Time required to execute 500 tasks with 6-stages pipeline = Time taken by 1st task + Time taken by
remaining 499 tasks
= 1 x 6 clock cycles + 499 x 1 clock cycle
= 6 clock time + 499 clock time
= 6* 10 + 499* 10
= 60 + 4990 = 5050ns
