Computer System Architecture Subject Wise UGC NET Question Analysis

Computer System Architecture PYQ Part-2


Q.1➡ | UGC NET DEC 2023
The average time required to search a storage location in memory and obtain its contents is called:
i ➥ Access time
ii ➥ Latency time
iii ➥ Response time
iv ➥ Reading time
Best Explanation:
Answer: (I)
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Q.2➡ | UGC NET DEC 2023
Match List – I with List – II.
List – I

(A) SZA
(B) SKI
(C) SNA
(D) ISZ

List – II
(I) Increment M and skip it zero
(II) Skip if AC is negative
(III) Skip if input flag is on
(IV) Skip if AC is Zero

Choose the correct answer from the options given below :
i ➥ (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
ii ➥ (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
iii ➥ (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
iv ➥ (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
Best Explanation:
Answer: (II)
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Q.3➡ | UGC NET DEC 2023
The microoperation which divides a signed binary number by 2 is:
i ➥ Circular shift
ii ➥ Logical shift
iii ➥ Arithmetic shift right
iv ➥ Arithmetic shift left
Best Explanation:
Answer: (II)
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Q.4➡ | UGC NET DEC 2023
Which of the following statements is/are NOT CORRECT about NUMA?
(A) LOAD and STORE instructions are used to access remote memory.
(B) There is a single address space visible to all CPU.
(C) Access to local memory is slower than access to remote memory.
(D) When the access time to remote memory is hidden, the system is called NC – NUMA.
(E) In CC-NUMA, Coherent caches are present.
Choose the correct answer from the options given below :
i ➥ (A) and (C) Only
ii ➥ (B) and (D) Only
iii ➥ (A) and (E) Only
iv ➥ (C) and (D) Only
Best Explanation:
Answer: (IV)
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Q.5➡ | UGC NET DEC 2023
The interface(s) that provide(s) I/O transfer of data directly to and from the memory unit peripheral is/are termed as:
(A) DMA (Direct Memory Access)
(B) IOP (Input-Output Processor)
(C) Serial Interface
(D) Parallel Interface
Choose the correct answer from the options given below :
i ➥ (A) Only
ii ➥ (B) Only
iii ➥ (A) and (B) Only
iv ➥ (C) and (D) Only
Best Explanation:
Answer: (III)
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Q.6➡ | UGC NET DEC 2023
A system bus in which each data item is transferred during a time slice known in advance to both units source and destination is called:
i ➥ MIMD
ii ➥ DMA
iii ➥ asynchronous bus
iv ➥ synchronous bus
Best Explanation:
Answer: (IV)
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Q.7➡ | UGC NET DEC 2023
In most general case, the computer needs to process each instruction with the following sequence of steps:
(A) Calculate the effective address
(B) Execute the instruction
(C) Fetch the instruction from memory
(D) Fetch the operand from memory
(E) Decode the instruction
Choose the correct answer from the options given below:
i ➥ (A), (B), (C), (D), (E)
ii ➥ (A), (B), (C), (E), (D)
iii ➥ (C), (E), (A), (D), (B)
iv ➥ (C), (E), (D), (A), (B)
Best Explanation:
Answer: (III)
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Q.8➡ | UGC NET JUNE 2023
A processor chip is used for application in which 30% of execution time is spent on floating point addition. For the new model of the processor, the design team has come up with redesign the floating point adder to make it twice as fast. What will be possible maximum speed up by this redesign?
i ➥ 2.0
ii ➥ 1.06
iii ➥ 1.18
iv ➥ 2.5
Best Explanation:
Answer: III
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Q.9➡ | UGC NET JUNE 2023
256Mb DRAM is organized as a 32M×8 memory externally and as a 16 K×16 K square array internally. Each row must be refreshed at least once every 50 mili second to forestall loss of data; refreshing one row takes 100 nanoseconds. What fraction of the total memory bandwidth is lost to refresh cycles?
i ➥ 6.6%
ii ➥ 3.3%
iii ➥ 9.9%
iv ➥ 4.3%
Best Explanation:
Answer: II
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Q.10➡ | NET December 2022
Which one of the following type of memory is fastest
i ➥ Cache memory
ii ➥ Register memory
iii ➥ Main memory
iv ➥ Secondary memory
Best Explanation:
Answer: (ii)
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Q.11➡ | NET December 2022
Consider an unpipelined machine with 10nsec clock cycles which uses four cycles for ALU operations and branches where as five cycles for memory operation. Assume that the relative frequencies of these operations are : 40%, 20% and 40 %, respectively. Due to clock skew and setup pipeline let us consider that the machine adds one nsec overhead to the clock. How much speedup is observed in the instruction execution rate when a pipelined machine is considered?
i ➥ 2 times
ii ➥ 4 times
iii ➥ 6 times
iv ➥ 8 times
Best Explanation:
Answer: (ii)
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Q.12➡ | NET December 2022
Which of the following is/are true for Dynamic RAM (DRAM) ?
(A) It is slower than static RAM (SRAM)
(B) Packing Density is Higher than Static RAM (SRAM)
(C) It’s faster than Static RAM (SRAM)
(D) It is requires data refreshing
which of the correct answer from the options given below :
i ➥ A, B and D only
ii ➥ A, B and C only
iii ➥ C and D only
iv ➥ B and D only
Best Explanation:
Answer: (i)
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Q.13➡ | NET December 2022
Which of the following statement is/are false?
A : The processor has direct access to both primary and secondary memory
B : Primary memory stores the active instructions and data for the program being executed on the process
C : Secondary memory is used as a backup memory
D : memory system is implemented on a single level memory
Choose the correct answer from the options given below :
i ➥ A and B only
ii ➥ B and C only
iii ➥ A, B and C only
iv ➥ A and D only
Best Explanation:
Answer: (iv)
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Q.14➡ | NET December 2022
Match List (I) with List (II)
A.	Direct addressing	I.	MVI A, FFH
B.	Indirect Addressing	II.	MOV A , B
C. 	Register Indirect	III.	STA FFFFH
D. 	Immediate Addressing	IV.	MOV A, M
Choose the correct answer from the options given below:
i ➥ A-(I), B-(II), C-(III), D-(IV)
ii ➥ A-(II), B-(III), C-(IV), D-(I)
iii ➥ A-(III), B-(IV), C-(II), D-(I)
iv ➥ A-(IV), B-(III), C-(I), D-(II)
Best Explanation:
Answer: (iii)
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Q.15➡ | NET December 2022
The Correct sequence in fetch- executes cycle is ………….
(A) Decode
(B) Fetch
(C) Execute
Choose the correct answer from the following
i ➥ A-B-C
ii ➥ B-C-A
iii ➥ C-B-A
iv ➥ B-A-C
Best Explanation:
Answer: (iv)
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Q.16➡ | NET June 2022
In a cache memory , if address has 9 bits in Tag field and 12 bits in index field, the size of main memory and cache memory would be respectively
i ➥ 2K, 4K
ii ➥ 1024K, 2K
iii ➥ 4K, 2048K
iv ➥ 2048K, 4K
Best Explanation:
Answer: (iv)
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Q.17➡ | NET June 2022
Consider the following related to Fourth Generation Technique (4GT):
(A) It controls efforts
(B) It controls resources
(C) It controls cost of development.
Choose the correct answer from the options given below:
i ➥ (A) and (B) only
ii ➥ (B) and (C) only
iii ➥ (C) and (A) only
iv ➥ All (A), (B) and (C)
Best Explanation:
Answer: (iv)
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Q.18➡ | NET June 2022
Consider a memory system having address spaced at a distance of m , T = Bank cycle time and n number of banks , then the average data access time per word access in synchronous organization is
i ➥ Consider a memory system having address spaced at a distance of m , T = Bank cycle time and n number of banks , then the average data access time per word access in synchronous organization is
ii ➥ Consider a memory system having address spaced at a distance of m , T = Bank cycle time and n number of banks , then the average data access time per word access in synchronous organization is
iii ➥ Consider a memory system having address spaced at a distance of m , T = Bank cycle time and n number of banks , then the average data access time per word access in synchronous organization is
iv ➥ Consider a memory system having address spaced at a distance of m , T = Bank cycle time and n number of banks , then the average data access time per word access in synchronous organization is
Best Explanation:
Answer: (i)
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Q.19➡ | NET June 2022
The total storage capacity of a floppy disk having 80 tracks and storing 128 bytes/sector is 163,840 bytes . How many sectors does this disk have ?
i ➥ 27
ii ➥ 2048
iii ➥ 4K
iv ➥ 16
Best Explanation:
Answer: (iv)
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Q.20➡ | NET June 2022
Given below are statements:
Statement (I) ; Consider 20 bit  ‘Branch’ microinstruction code format given below
		3	3	3	2	2	7	
F1	F2	F3	CD	BR	AD

         F1, F2, F3 : Micro-operation fields
	CD  :  Condition for branching
	BR  :   Branch field	
	AD :  	Address field
Statement (II) : Instruction represented in above format can perform branch in 4 condition.
In the light of the above statements, choose the most appropriate answer from the options given below:
i ➥ Both statement (I) and Statement (II) are correct
ii ➥ Both statement (I) and Statement (II) are incorrect
iii ➥ Statement (I) is correct and Statement (II) are incorrect
iv ➥ Statement (I) is incorrect and Statement (II) are correct
Best Explanation:
Answer: (i)
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Q.21➡ | NET June 2022
A 4-stage pipeline has the delay as 150, 120, 160 and 140 ns respectively . registers that are used between the stage have delay of 5 ns. Assuming constant locking rate , the total time required to process 1000 data items on this pipeline is
i ➥ 160.5 ns
ii ➥ 165.5 ns
iii ➥ 120.5 ns
iv ➥ 590.5 ns
Best Explanation:
Answer: (ii)
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Q.22➡ | NET June 2022
A magnetic tape drive has transport speed of 200 inches per second and a recording density of 1600 bytes per inch. The time required to write 600000 bytes of date grouped in 100 charaters record with a blocking factor 10 is
i ➥ 2.0625 sec
ii ➥ 2.6251 sec
iii ➥ 2.0062 sec
iv ➥ 2.6150 sec
Best Explanation:
Answer: (i)
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Q.23➡ | NET June 2021
Given below are three statements related to interrupt handling mechanism
A. Interrupt handler routine is not stored at a fixed address in the memory.
B. CPU hardware has a dedicated wire called the interrupt request line used for handling interrupts
C. Interrupt vector contains the memory addresses for speciaized interrupt handlers.
In the context of above statements, choose the correct answer from the options given below: Options:-
i ➥ A is TRUE only
ii ➥ Both A and B are TRUE only
iii ➥ Both A, C are TRUE only
iv ➥ Both B and C are TRUE only

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Answer: IV
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Q.24➡ | NET June 2021
Which of the following statement is true?
A. Control memory is part of the hardwired control unit.
B. Program control instructions are used to alter the sequential flow of the program.
C. The register indirect addressing mode for accessing memory operand is similar to displacement addressing mode.
D. CPU utilization is not affected by the introduction of Interrupts.
i ➥ A
ii ➥ B
iii ➥ C
iv ➥ D

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Answer: II
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Q.25➡ | NET June 2021
Which of the following is not an example of pseudo-instruction?
i ➥ DEC
ii ➥ END
iii ➥ HLT
iv ➥ ORG

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Answer: III
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Q.26➡ | NET June 2021
Given below are two statements
Statement I: CISC computers have a large of number of addressing modes.
Statement II: In RISC machines memory access is limited to load and store instructions.
In light of the above statements, choose the correct answer from the options given below
i ➥ Both Statement I and Statement II are false
ii ➥ Both Statement I and Statement II are true
iii ➥ Statement I is false but Statement II is true
iv ➥ Statement I is true but Statement II is false

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Answer: II
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Q.27➡ | NET June 2021
The cache coherence problem can be solved
A. by having multiport memory
B. allow only nonshared data to be stored in cache
C. using a snoopy cache controller
D. using memory interleaving
Choose the correct answer from the options given below:
i ➥ A and C only
ii ➥ B and C only
iii ➥ B and D only
iv ➥ D and C only

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Answer: II
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Q.28➡ | NET June 2021
Arrange the following in the increasing order of complexity.
A. I/O Module
B. I/O processor
C. I/O Channel
D. DMA
Choose the correct answer from the options given below Options:-
i ➥ A, B, C, D
ii ➥ A, D, C, B
iii ➥ C, D, A, B
iv ➥ D, C, B, A

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Answer: II
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Q.29➡ | UGC NET November 2020
Consider a single-level page table system, with the page table stored in the memory. If the hit rate to TLB is 80%, and it takes 15 nanoseconds to search the TLB, and 150 nanoseconds to access the main memory, then what is the effective memory access time, in nanoseconds?
i➥ 185
ii ➥ 195
iii ➥ 205
iv ➥ 175

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Answer: II
Explanation:
It is given that,
hit ratio = 0.8 or 80% ,
memory access time = 150 ns,
TLB access time = 15ns,
Miss ratio = 1- hit ratio = 1 – 0.8 = 0.2

Effective memory access time
= hit ratio (memory access time + TLB access time) + miss ratio (2memory access time + TLB access time)
= 0.8(150 + 15) + 0.2* (2150 + 15)
= 0.8 165 + 0.2 * 315
= 132 + 63
= 195 ns

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Q.30➡ | UGC NET November 2020
A non-pipeline system takes 50ns to process a task. The same task can be processed in a six-segment pipeline with a clock cycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks.
i➥ 6
ii ➥ 4.95
iii ➥ 5.7
iv ➥ 5.5
Answer: II

Explanation:
Given,
Total Stage (k) = 6
Time taken by non-pipeline system(Tnp) = 50ns
Time taken by pipeline system(Tp) = 10ns

Formula,
Time required to execute n tasks without pipeline = n*Tnp
Time required to execute n tasks with k-stages pipeline = = (k+n-1)*Tp

Let’s solve,
Time required to execute 500 tasks without pipeline = n*Tnp = 500* 50 = 25000 ns
Time required to execute 500 tasks with 6-stages pipeline = Time taken by 1st task + Time taken by remaining 499 tasks
 = 1 x 6 clock cycles + 499 x 1 clock cycle
 = 6 clock time + 499 clock time
 = 6* 10 + 499* 10
 = 60 + 4990 = 5050ns

or

Time required to execute 500 tasks with 6-stages pipeline
= (k+n-1)*Tp
=(6+500-1)*10
= 505*10
= 5050ns


Therefore, Option(II) is correct.
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Q.31➡ | UGC NET November 2020
Consider a machine with a byte addressable main memory of 216 bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How many bits will be there in Tag, line and word field of format of main memory addresses?
i➥ 8,5,3
ii ➥ 8,6,2
iii ➥ 7,5,4
iv ➥ 7,6,3

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Answer: I
Explanation:
Direct mapped cache:
In a direct-mapped cache structure, the cache is organized into multiple set with a single cache line per set. Based on the address of the memory block, it can only occupy a single cache line. The cache can be framed as a (n*1) column matrix.

Main memory offset
Consider a machine with a byte addressable main memory of 2616 bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How many bits will be there in Tag, line and word field of format of main memory addresses?
In above,
Main memory size = 216 B
Block size = 8 B = 23 B , Block offset = 3
Cache line = 32 B = 25 B,  Cache line offset = 5
 
Consider a machine with a byte addressable main memory of 2616 bytes and block size of 8 bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. How many bits will be there in Tag, line and word field of format of main memory addresses?

Tag bits = main memory offset – (line offset + Block offset)
               = 16 – (5 + 3)
               = 16 – 8 = 8

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Q.32➡ | UGC NET November 2020
Given below are two statements:
Statement I: hardwired control unit can be optimized to produce fast mode of operation.
Statement II: Indirect addressing mode needs two memory references to fetch the operand.

In the light of the above statements, choose the correct answers from the options given below
i➥ Both Statement I and Statement II are true
ii ➥ Both Statement I and Statement II are false
iii ➥ Statement I is correct but Statement II is false
iv ➥ Statement I is incorrect but Statement II is true

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Answer: I
Explanation:
Statement I: hardwired control unit can be optimized to produce fast modes of operations.
hardwired control unit can be uses a large number of registers and because of that it is costly.
hardwired control unit Instruction size in the Hardwired unit is fixed.
hardwired control unit has a small number of addressing modes.
Statement(I) is True
Statement II: Indirect addressing mode needs two memory references to fetch the operand.
In indirect addressing mode, instructions contain the address of an operand where operand is actually present. It requires two memory access to fetch the operand.
Example:
LOAD R1, @300
Given below are two statements: Statement I: hardwired control unit can be optimized to produce fast mode of operation. Statement II: Indirect addressing mode needs two memory references to fetch the operand. In the light of the above statements, choose the correct answers from the options given below A) Both Statement I and Statement II are true B) Both Statement I and Statement II are false C) Statement I is correct but Statement II is false D) Statement I is incorrect but Statement II is true
The address part of an instruction contains 300. Now the control go at address 300 to find the address of an operand. The address of an operand in this example is 500. The operand found at loaction 500. Indirect Addreesing need two memory reference, one for to find address of an operand & another one for operand itself.
Statement(I) is True

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Q.33➡ | UGC NET November 2020
Match list I and List II
Match list I and List II  (a) handshaking (i) i/o interface inform the CPU that device is ready to transfer
Choose the correct answer from the options given below:
i➥ A-I, B-II, C-III, D-IV
ii ➥ A-II, B-IV, C-III, D-I
iii ➥ A-II, B-IV, C-I, D-III
iv ➥ A-IV, B-III, C-II, D-I

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Answer: III
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Q.34➡ | UGC NET November 2020
Arrange the following types of machine in descending order of complexity.
(A) SISD
(B) MIMD
(C) SIMD
Choose the correct answer from the options given below:
i➥ A, B, C
ii ➥ C, B, A
iii ➥ B, C, A
iv ➥ C, A, B

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Answer: III
Explanation:
MIMD < SIMD < SISD

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Q.35➡ | UGC NET November 2020
Which of the following statements with respect to K-segment pipelining are true?
A) Maximum speedup that a pipeline can provide is k theoretically.
B) It is impossible to achieve maximum speedup k in the k-segment pipeline.
C) All segments in the pipeline take the same time in computation.

Choose the correct answer from the options given below:
i➥ (A) and (B) only
ii ➥ (B) and (C) only
iii ➥ (A) and (C) only
iv ➥ (A), (B) and (C)

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Answer: I
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Q.36➡ | UGC NET November 2020
The following program is stored in the memory unit of the basic computer. What is the content of the accumulator after the execution of the program? (All location numbers listed below are in hexadecimal)
The following program is stored in the memory unit of the basic computer. What is the content of the accumulator after the execution of the program? (All location numbers listed below are in hexadecimal) A) 1002H B) 2011H C) 2022H D) 0215H
i➥ 1002H
ii ➥ 2011H
iii ➥ 2022H
iv ➥ 0215H
Answer: IV
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Q.37➡ | UGC NET November 2020
The period of a signal is 100ms. then the frequency of this signal in kilohertz is __?
i➥ 10
ii ➥ 10-1
iii ➥ 10-2
iv ➥ 10-3

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Answer: III
Explanation:
Period = 100 ms = 100*10-3 = 10-1s
Frequency
= 1 / period
= 1 / 100*10-3
= (1 / 10-1) Hz
= (1 / 10-1 * 103) KHz
= 1 / 102 KHz
= 10-2 KHz

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Q.38➡ | NTA UGC NET November 2020
Comprehension: Question 16-20 concerns a disk with a sector size of 512 bytes, 2000 tracks per surface.50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.

Q16: If one track of data can be transferred per revolution, then what is the data transfer rate?
i➥ 2,850 KBytes/second
ii ➥ 4,500 KBytes/second
iii ➥ 5,700 KBytes/second
iv ➥ 2,250 KBytes/second

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Answer: IV
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Q.39➡ | NTA UGC NET November 2020
Comprehension: Question 16-20 concerns a disk with a sector size of 512 bytes, 2000 tracks per surface.50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.

Q17: Given below are two statements:
Statement I: The disk has a total number of 2000 cylinders.
Statement II: 51200 bytes is not a valid block size for the disk.

In the light of the above statements, choose the correct answer from the options given below:
i➥ Both Statement I and Statement II are true
ii ➥ Both Statement I and Statement II are false
iii ➥ Statement I is correct but Statement II is false
iv ➥ Statement I is incorrect but Statement II is true

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Answer: I
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Q.40➡ | NTA UGC NET November 2020
Comprehension: Question 16-20 concerns a disk with a sector size of 512 bytes, 2000 tracks per surface.50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.

Q18: If T is the capacity of a track in bytes, and S is the capacity of each surface in bytes, then (T,S) = __________.
i➥ (50 K, 50000 K)
ii ➥ (50 K, 50000 K)
iii ➥ (25 K, 50000 K)
iv ➥ (40 K, 36000 K)

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Answer: III
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Q.41➡ | NTA UGC NET November 2020
Comprehension: Question 16-20 concerns a disk with a sector size of 512 bytes, 2000 tracks per surface.50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.

Q19: What is the capacity of the disk, in bytes?
i➥ 25,000 K
ii ➥ 500,000 K
iii ➥ 250,000 K
iv ➥ 50,000 K

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Answer: II
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Q.42➡ | UGC NET November 2020
Comprehension: Question 16-20 concerns a disk with a sector size of 512 bytes, 2000 tracks per surface.50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.

Q20: If the disk platters rotate at 5400 rpm (revolutions per minute), then approximately what is the maximum rotational delay?
i➥ 0.011 seconds
ii ➥ 0.11 seconds
iii ➥ 0.0011 seconds
iv ➥ 1.1 seconds

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Answer: I
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Q.43➡ | UGC NET December 2019
A Non-pipelined system takes 30ns to process a task. The same task can be processed in a four-segment pipeline with a clock cycle of 10ns. Determine the speed up of the pipeline for 100 tasks
i➥ 3
ii ➥ 4
iii ➥ 3.91
iv ➥ 2.91

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Answer: IV
Explanation:
Time required to execute 100 tasks without pipeline = 100* 30 = 3000 ns
Time required to execute 100 tasks with 4-stages pipeline
= Time taken by 1st task + Time taken by remaining 99 tasks
= 1 * 4 clock cycle + 99 * 1 clock cycle
= 4 * 10 + 99 * 10
= 40 + 990
= 1030 ns
Speedup
= Time required without pipeline / Time required with pipeline
= 3000 / 1030
= 2.91
Or
Speedup
= Time required without pipeline / Time required with pipeline
= n * Tn / (n + k – 1) Tp

where,
Tn = clock cycle without pipeline,
n = total number of tasks,
k = number of segment,
Tp = clock cycle with pipeline

Speedup
= n * Tn / (n + k – 1) Tp
= 100 * 30 / (100 + 4 – 1) * 10
= 3000 / 1030
= 2.91 ns

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Q.44➡ | UGC NET December 2019
The reduced Instruction Set Computer (RISC) characteristics are:
(a) Single cycle instruction execution
(b) Variable length instruction formats
(c) Instructions that manipulates operands in memory
(d) Efficient instruction pipeline

Choose the correct characteristics from the options given below:
i➥ (a) and (b)
ii ➥ (b) and (c)
iii ➥ (a) and (d)
iv ➥ (c) and (d)

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Answer: III
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Q.45➡ | UGC NET December 2019
A micro instruction format has micro operation field which is divided into 2 sub fields F1 and F2. Each having 15 distinct micro operations condition field CD for four status bits. Branch field BR having four options used in conjunction with address field AD. The address space is of 128 memory words. The size of micro instruction is
i➥ 19
ii ➥ 18
iii ➥ 17
iv ➥ 20

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Answer: III
Explanation:
A microinstruction format has microoperation field which is divided into 2 subfields F1 and F2.
Each having 15 distinct micro operations.
Bits required =log215 = 3 bits each

Condition field CD have four status bits.
Bits required = log2 4 = 2 bits

Branch field BR having four options used in conjunction with address field AD.
Bits required = log2 4 = 2 bits

The address space is of 128 memory words.
Bits required = log2 128 = 7 bits
A microinstruction format has microoperation field which is divided into 2 subfields F1 and F2. Each having 15 distinct micro operations condition field CD for four status bits. Branch field BR having four options used in conjunction with address field AD. The address space is of 128 memory words. The size of micro instruction is A)	19 B)	18 C)	17 D)	20
Micro instruction size
= F1 + F2 + CD + BR + ADR
= 3+3+2+2+7
= 17 bits

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Q.46➡ | UGC NET December 2019
Consider a paging system where translation lookaside buffer (TLB) a special type of associative memory is used with hit ratio of 80%.
Assume that memory reference takes 80 nanoseconds and reference time to TLB is 20 nanoseconds. What will be the effective memory access time given 80% hit ratio?
i➥ 110 nanoseconds
ii ➥ 116 nanoseconds
iii ➥ 200 nanoseconds
iv ➥ 100 nanoseconds

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Answer: II
Explanation:
It is given that ,

TLB access time = 20ns
Memory access time = 80ns
hit ratio = 80% (or 0.8)
miss ratio = 1 – 0.8 = 0.2(or 20%)

effective memory access
= hit ratio * (TLB access time + memory access time) + miss ratio * (TLB access time + memory access time)
= 0.8(20+80) + 0.2(20+280)
= 0.8 * 100 + 0.2*180
= 80 + 36
= 116 ns

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Q.47➡ | UGC NET December 2019
A computer uses a memory unit of 512 K words of 32 bits each. A binary instruction code is stored in one word of the memory. The instruction has four parts: an addressing mode field to specify one of the two-addressing mode (direct and indirect), an operation code, a register code part to specify one of the 256 registers and an address part. How many bits are there in addressing mode part, opcode part, register code part and the address part?
i ➥ 1, 3, 9, 19
ii ➥ 1, 4, 9, 18
iii ➥ 1, 4, 8, 19
iv ➥ 1, 8, 8, 20

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Answer: III
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Q.48➡ | UGC NET December 2019
Match List-I and List-II:

Choose the correct option from those given below:
i ➥ (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
ii ➥ (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
iii ➥ (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
iv ➥ (a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)

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Answer: III
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Q.49➡ | UGC NET December 2019
An instruction is stored at location 500 with it address field at location 501. The address field has the value 400. A processor register R1 contains the number 200. Match the addressing mode (List-I) given below with effective address (List-II) for the given instruction:

Choose the correct option from those given below:
i ➥ (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
ii ➥ (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
iii ➥ (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
iv ➥ (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

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Answer: I
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Q.50➡ | UGC NET December 2019
Match List-I and List-II:

Choose the correct option from those given below:
i ➥ (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
ii ➥ (a)-(iv), (b).(iii), (c)-(i), (d)-(ii)
iii ➥ (a)-(iii), (b)-(iv), (c)-(i), (d)-(i)
iv ➥ (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)

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Answer: I
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Q.51➡ | UGC NET December 2019
The following program is stored in the memory unit of the basic computer. Give the content of accumulator register in hexadecimal after the execution of the program.
i ➥ A1B4
ii ➥ 81B4
iii ➥ A184
iv ➥ 8184

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Answer: I
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Q.52➡ | UGC NET June 2019
Which type of addressing mode, less number of memory references are required?
i ➥ Immediate
ii ➥ Implied
iii ➥ register
iv ➥ indexed

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Answer: marks are given to all in this question by NTA
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Q.53➡ | UGC NET June 2019
Suppose that the register A and register K have the bit configuration. Only the three leftmost bits of A are compared with memory words because K has 1’s in these positions. Because of its organization, this type of memory is uniquely suited to parallel searches by data association. This type of memory is known as
i ➥ RAM
ii ➥ ROM
iii ➥ Content addressable memory
iv ➥ Secondary memory

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Answer: III
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Q.54➡ | UGC NET June 2019
For a magnetic disk with concentric circular tracks, the seek latency is not linearly proportional to the seek distance due to
i ➥ Non-Uniform distribution of requests
ii ➥ arm starting or stopping inertia
iii ➥ higher capacity of tracks on the periphery of the plate
iv ➥ use of unfair arm scheduling policies

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Answer: II
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Q.55➡ | UGC NET June 2019
The fault can be easily diagnosed in the micro-program control unit using diagnostic tools by maintaining the contents of.
i ➥ Flags and Counters
ii ➥ Registers and counters
iii ➥ Flags and registers
iv ➥ Flags, registers and counters

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Answer: IV
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Q.56➡ | UGC NET June 2019
Suppose that a computer program takes 100 seconds of execution time on a computer with multiplication operation responsible for 80 seconds of this time. How much do you have to improve the speed of multiplication operation if you are asked to execute this program four times faster.
i ➥ 14 times faster
ii ➥ 15 times faster
iii ➥ 16 times faster
iv ➥ 17 times faster

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Answer: III
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Q.57➡ | UGC NET December 2018
Consider a disk pack with 32 surfaces, 64 tracks and 512 sectors per pack. 256 bytes of data are stored in a bit serial manner in a sector. The number of bits required to specify a particular sector in the disk is.
i ➥ 19
ii ➥ 20
iii ➥ 18
iv ➥ 22

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Answer: II
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Q.58➡ | UGC NET December 2018
Dirty bit is used to show the
i ➥ Page with low frequency occurrence
ii ➥ Wrong page
iii ➥ Page with corrupted data
iv ➥ Page that is modified after being loaded into cache memory

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Answer: IV
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Q.59➡ | UGC NET December 2018
Consider the following x86 – assembly language instructions :
MOV AL, 153
NEG AL
The contents of the destination register AL (in 8-bit binary notation), the status of Carry Flag(CF) and Sign Flag(SF) after the execution of above instructions, are
i ➥ AL = 0110 0110; CF = 0; SF =0
ii ➥ AL = 0110 0111; CF = 0; SF =1
iii ➥ AL = 0110 0110; CF = 1; SF =1
iv ➥ AL = 0110 0111; CF = 1; SF =0

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Answer: I
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Q.60➡ | UGC NET December 2018
Consider the following statements :
(i) Auto increment addressing mode is useful in creating self-relocating code.
(ii) If auto addressing mode is included in an instruction set architecture, then an additional ALU is required for effective address calculation.
(iii) In auto increment addressing mode, the amount of increment depends on the size of the data item accessed.
Which of the above statements is/are true ?
i ➥ (iii) only
ii ➥ (ii) and (iii) only
iii ➥ (i) and (ii) only
iv ➥ (ii) only

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Answer: I
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Q.61➡ | UGC NET June 2018
Normally user programs are prevented from handling I/O directly by I/O instructions in them. For CPUs having explicit I/O instructions, such I/O protection is ensured by having the I/O instructions privileged. In a CPU with memory mapped I/O, there is no explicit I/O instruction. Which one of the following is true for a CPU with memory mapped I/O ?
i ➥ I/O protection is ensured by operating system routines.
ii ➥ I/O protection is ensured by a hardware trap.
iii ➥ I/O protection is ensured during system configuration.
iv ➥ I/O protection is not possible.

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Answer: I
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Q.62➡ | UGC NET June 2018
Which of the following mapping is not used for mapping process in cache memory?
i ➥ Associative mapping
ii ➥ Direct mapping
iii ➥ Set-Associative mapping
iv ➥ Segmented – page mapping

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Answer: IV
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Q.63➡ | UGC NET June 2018
In 8085 microprocessor, what is the output of following program ? LDA 8000H MVI B, 30H ADD B STA 8001H
i ➥ Read a number from input port and store it in memory
ii ➥ Read a number from input device with address 8000H and store it in memory at location 8001H
iii ➥ Read a number from memory at location 8000H and store it in memory location 8001H
iv ➥ Load A with data from input device with address 8000H and display it on the output device with address 8001H

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Answer: III
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Q.64➡ | UGC NET November 2017 Paper-3
In 8085 microprocessor which of the following flag(s) is (are) affected by an arithmetic operation?
i ➥ AC flag Only
ii ➥ CY flag Only
iii ➥ Z flag Only
iv ➥ AC, CY, Z flags

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Answer: IV
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Q.65➡ | UGC NET November 2017 Paper-3
In 8085 microprocessor the address bus is of________bits.
i ➥ 4
ii ➥ 8
iii ➥ 16
iv ➥ 32

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Answer: III
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Q.66➡ | UGC NET November 2017 Paper-3
In the architecture of 8085 microprocessor match the following:

Code:
i ➥ (a)-(iv), (b)-(i), (c)-(ii)
ii ➥ (a)-(iii), (b)-(iv), (c)-(ii)
iii ➥ (a)-(ii), (b)-(iii), (c)-(i)
iv ➥ (a)-(i), (b)-(ii), (c)-(iv)

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Answer: II
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Q.67➡ | UGC NET November 2017 Paper-3
Which of the following addressing mode is best suited to access elements of an array of contiguous memory locations ?
i ➥ Indexed addressing mode
ii ➥ Base Register addressing mode
iii ➥ Relative address mode
iv ➥ Displacement mode

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Answer: I
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Q.68➡ | UGC NET November 2017 Paper-3
Which of the following is correct statement ?
i ➥ In memory – mapped I/O, the CPU can manipulate I/O data residing in interface registers that are not used to manipulate memory words.
ii ➥ The isolated I/O method isolates memory and I/O addresses so that memory address range is not affected by interface address assignment.
iii ➥ In asynchronous serial transfer of data the two units share a common clock.
iv ➥ In synchronous serial transmission of data the two units have different clocks.

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Answer: II
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Q.69➡ | UGC NET November 2017 Paper-3
A micro-instruction format has micro-ops field which is divided into three sub-fields F1, F2, F3 each having seven distinct micro-operations, condition field CD for four status bits, branch field BR having four options used in conjunction with address field ADF. The address space is of 128 memory locations. The size of micro-instruction is:
i ➥ 17
ii ➥ 20
iii ➥ 24
iv ➥ 32

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Answer: II
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Q.70➡ | UGC NET November 2017 Paper-3
Consider the following assembly program fragment :
stc
mov al, 11010110b
mov cl, 2
rcl al, 3
rol al, 4
shr al, cl
mul cl
The contents of the destination register ax (in hexadecimal) and the status of Carry Flag (CF) after the execution of above instructions, are:
i ➥ ax=003CH; CF=0
ii ➥ ax=001EH; CF=0
iii ➥ ax=007BH; CF=1
iv ➥ ax=00B7H; CF=1

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Answer: I
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Q.71➡ | UGC NET January 2017 Paper-3
Which of the following is an interrupt according to temporal relationship with system clock?
i ➥ Maskable interrupt
ii ➥ Periodic interrupt
iii ➥ Division by zero
iv ➥ Synchronous interrupt

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Answer: IV
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Q.72➡ | UGC NET January 2017 Paper-3
The general configuration of the micro-programmed control unit is given below:

What are blocks B and C in the diagram respectively?
i ➥ Block address register and cache memory
ii ➥ Control address register and control memory
iii ➥ Branch register and cache memory
iv ➥ Control address register and random access

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Answer: II
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Q.73➡ | UGC NET January 2017 Paper-3
Match the following :
i ➥ a-(iv), b-(iii), c-(i), d-(ii)
ii ➥ a-(iv), b-(i), c-(iii), d-(ii)
iii ➥ a-(iv), b-(ii), c-(i), d-(iii)
iv ➥ a-(iv), b-(iii), c-(ii), d-(i)

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Answer: I
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Q.74➡ | UGC NET January 2017 Paper-3
In 8085 microprocessor, the digit 5 indicates that the microprocessor needs:
i ➥ –5 volts, +5 volts supply
ii ➥ +5 volts supply only
iii ➥ –5 volts supply only
iv ➥ 5 MHz clock

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Answer: II
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Q.75➡ | UGC NET January 2017 Paper-3
In 8085, which of the following performs : load register pair immediate operation?
i ➥ LDAX rp
ii ➥ LHLD addr
iii ➥ LXI rp, data
iv ➥ INX rp

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Answer: III
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NTA UGC NET Subject Wise Previous Year Question With Solutions

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