UGC NET 2021 | What is the minimum number of bits needed
| Comprehension: Read the following and answer the questions: Consider a machine with 16 GB main memory and 32-bits virtual address space, with page size as 4KB. Frame size and page size is same for the given machine. What is the minimum number of bits needed for the physical address? |
| i➥ 12 |
| ii➥ 24 |
| iii➥ 28 |
| iv➥ 34 |
Answer: Option IV
Solution:
Given,
Main Memory Size = 16GB = 234.
Formula used,
Physical Address Space = ⌈log2(size of main memory)⌉.
Calculation,
Physical Address Space = ⌈log2 234⌉
= ⌈34*log22⌉
= ⌈34⌉
= 34 bits
Note: log22 = 1
Therefore, Minimum 34 bits needed for physical Address Space.
So, Option(IV)is correct.
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